4x^2-x(2-x)+2(x-1)=3

Solution for 4x^2-x(2-x)+2(x-1)=3 equation:

Simplifying
4x2 + -1x(2 + -1x) + 2(x + -1) = 3
4x2 + (2 * -1x + -1x * -1x) + 2(x + -1) = 3
4x2 + (-2x + 1x2) + 2(x + -1) = 3

Reorder the terms:
4x2 + -2x + 1x2 + 2(-1 + x) = 3
4x2 + -2x + 1x2 + (-1 * 2 + x * 2) = 3
4x2 + -2x + 1x2 + (-2 + 2x) = 3

Reorder the terms:
-2 + -2x + 2x + 4x2 + 1x2 = 3

Combine like terms: -2x + 2x = 0
-2 + 0 + 4x2 + 1x2 = 3
-2 + 4x2 + 1x2 = 3

Combine like terms: 4x2 + 1x2 = 5x2
-2 + 5x2 = 3

Solving
-2 + 5x2 = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 5x2 = 3 + 2

Combine like terms: -2 + 2 = 0
0 + 5x2 = 3 + 2
5x2 = 3 + 2

Combine like terms: 3 + 2 = 5
5x2 = 5

Divide each side by '5'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}